Steven D'Aprano wrote:
A / \ C B \ / D / \ E FYes, a super call might jog left from C to B, but only when being called from one of the lower classes D-F. That's still an upwards call relative to the originator, not sidewards.
But it's not an upward call relative to the class mentioned in the super() call, which is why I say it's misleading. -- Greg -- http://mail.python.org/mailman/listinfo/python-list