Steven D'Aprano wrote:

      A
     / \
    C   B
     \ /
      D
     / \
    E   F

Yes, a super call might jog left from C to B, but only when being called from one of the lower classes D-F. That's still an upwards call relative to the originator, not sidewards.

But it's not an upward call relative to the class mentioned
in the super() call, which is why I say it's misleading.

--
Greg
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