Lee Sander wrote: > Hi, > Suppose I have a string such as this > 'aabccccccefggggghiiijkr' > > I would like to print out all the positions that are flanked by a run > of symbols. > So for example, I would like to the output for the above input as > follows: > > 2 b 1 aa > 2 b -1 cccccc > 10 e -1 cccccc > 11 f 1 ggggg > 17 h 1 iii > 17 h -1 ggggg > > where the first column is the position of interest, the next column is > the entry at that position, > 1 if the following column refers to a runs that come after and -1 if > the runs come before
Trying to follow your spec I came up with from itertools import groupby from collections import namedtuple Item = namedtuple("Item", "pos key size") def compact(seq): pos = 0 for key, group in groupby(seq): size = len(list(group)) yield Item(pos, key, size) pos += size def window(items): items = iter(items) prev = None cur = next(items) for nxt in items: yield prev, cur, nxt prev = cur cur = nxt yield prev, cur, None items = compact("aabccccccefggggghiiijkr") for prev, cur, nxt in window(items): if cur.size == 1: if prev is not None: if prev.size > 1: print cur.pos, cur.key, -1, prev.key*prev.size if nxt is not None: if nxt.size > 1: print cur.pos, cur.key, 1, nxt.key*nxt.size However, this gives a slightly differenct output: $ python homopolymers.py 2 b -1 aa 2 b 1 cccccc 9 e -1 cccccc 10 f 1 ggggg 16 h -1 ggggg 16 h 1 iii 20 j -1 iii Peter -- http://mail.python.org/mailman/listinfo/python-list