Thanks...that worked. I have also been trying to get the return code and standard error.
How do I access these? #!/usr/bin/python import os import subprocess process=subprocess.Popen(['lpr', '-P' ,'raserlpr','/etc/hosts'], shell=False, stdout=subprocess.PIPE, stderr=subprocess.PIPE) print process.communicate() On 4 Aug, 12:08, Peter Otten <__pete...@web.de> wrote: > loial wrote: > > I am am trying to run the following command via subprocess > > > lpr -P printqueue filetoprint > > > I cannot seem to get it to work and return stderr > > > I think the issue is how to specify the arguments > > > I am trying > > > subprocess.Popen(['lpr -P' ,'laserlpr','/etc/hosts'], shell=False) > > This looks for an executable called "lpr -P"; try > > subprocess.Popen(['lpr', '-P' ,'laserlpr','/etc/hosts'], shell=False) > > > > > but get error : > > > Traceback (most recent call last): > > File "testopen.py", line 6, in ? > > subprocess.Popen(['lpr -P' ,'laserlpr','/etc/hosts'], shell=False) > > File "/usr/python2.4/lib/python2.4/subprocess.py", line 558, in __in > > it__ > > errread, errwrite) > > File "/usr/python2.4/lib/python2.4/subprocess.py", line 991, in _exe > > cute_child > > raise child_exception > > OSError: [Errno 2] No such file or directory- Hide quoted text - > > - Show quoted text - -- http://mail.python.org/mailman/listinfo/python-list