ernest wrote: > In this code: > > if set(a).union(b) == set(a): pass > > Does Python compute set(a) twice?
>>> a = "abc"
>>> b = "def"
>>> _set = set
>>> def set(x):
... print "computing set(%r)" % x
... return _set(x)
...
>>> if set(a).union(b) == set(a): pass
...
computing set('abc')
computing set('abc')
So yes, set(a) is computed twice.
Peter
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