On Wed, Sep 8, 2010 at 12:59 PM, cerr <ron.egg...@gmail.com> wrote: > Hi, > > I'm trying to create a listening socket connection on port 1514. > I tried to follow the documentation at: > http://docs.python.org/release/2.5.2/lib/socket-example.html > and came up with following lines: > import socket > > host = '' # Symbolic name meaning all available > interfaces > port = 1514 # Arbitrary non-privileged port > s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) > s.bind((host, port)) > s.listen(1) > conn, addr = s.accept() > print 'Connected by', addr > while 1: > data = conn.recv(1024) > if not data: break > conn.send(data) > conn.close() > but that is not working, i'm getting this: > import: unable to open X server `' @ error/import.c/ImportImageCommand/ > 362. > ./sockettest.py: line 4: host: command not found > ./sockettest.py: line 5: port: command not found > ./sockettest.py: line 6: syntax error near unexpected token `(' > ./sockettest.py: line 6: `s = socket.socket(socket.AF_INET, > socket.SOCK_STREAM)' > > now why would it try to open an x server??? :o > --
Because it's not executing it as a Python program. It's trying to execute it as a shell script. If you want to run a script as a Python program, either call the interpreter directly python sockettest.py or include a Shebang line as the first line of the file that tells the computer what interpreter to use #!/usr/bin/env python The file extension itself is meaningless to a Unix shell- it's just a part of the file name. -- http://mail.python.org/mailman/listinfo/python-list
