On 12/27/2010 6:05 PM, pyt...@bdurham.com wrote:
Is it possible to programmatically exit from the wsgiref's
serve_forever() loop?
I tried the following, all without success:
httpd.server_close()
httpd.shutdown()
sys.exit(1)
os._exit(1) (shouldn't this always abort an application?)
raise KeyboardInterupt (Ctrl+Break from console works)
>>> help(wsgiref.simple_server.WSGIServer.serve_forever)
Help on method serve_forever in module SocketServer:
serve_forever(self, poll_interval=0.5) unbound
wsgiref.simple_server.WSGIServer method
Handle one request at a time until shutdown.
Polls for shutdown every poll_interval seconds. Ignores
self.timeout. If you need to do periodic tasks, do them in
another thread.
>>> help(wsgiref.simple_server.WSGIServer.shutdown)
Help on method shutdown in module SocketServer:
shutdown(self) unbound wsgiref.simple_server.WSGIServer method
Stops the serve_forever loop.
Blocks until the loop has finished. This must be called while
serve_forever() is running in another thread, or it will
deadlock.
Did you try:
>>> import threading
>>> threading.Thread(target=httpd.shutdown).start()
Cheers,
Ian
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