On 24/01/2011 21:51, Alan wrote:
Why do function objects compare in this way to numbers?
Thanks,
Alan Isaac
def f(): return
...
f>5
True
In Python 2 any object can be compared in this way to any other. The
result is arbitrary but consistent.
In Python 3 that has changed because in practice it's more trouble than
it's worth:
>>> def f(): return
>>> f>5
Traceback (most recent call last):
File "<pyshell#2>", line 1, in <module>
f>5
TypeError: unorderable types: function() > int()
It's usually a good sign that there's a bug somewhere.
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