Chris Angelico <[email protected]> writes:
That loop will exit at the first gap in the sequence. If that's what
you want, you could try (untested):
from itertools import takewhile
seq = takewhile(lambda n: ('Keyword%d'%n) in dct, count(1))
lst = map(dct.get, seq)
This does 2 lookups per key, which you could avoid by making the code
uglier (untested):
sentinel = object()
seq = (dct.get('Keyword%d'%i,sentinel) for i in count(1))
lst = list(takewhile(lambda x: x != sentinel, seq))
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