On Thu, Apr 28, 2011 at 11:42 AM, Rusty Scalf <iai-...@sonic.net> wrote: > list1 = ['pig', 'horse', 'moose'] > list2 = ['62327', '49123', '79115'] > n = 2 > s2 = "list" + `n` > a = s2[list1.index('horse')] > print a > > -does not work
While advices above are indeed right way to go in your case, there is a way to get variable by its name. >>> list2 = ['62327', '49123', '79115'] >>> n = 2 >>> s2 = "list{0}".format(n) >>> print s2 list2 >>> print locals()[s2] ['62327', '49123', '79115'] >>> print locals()[s2][0] 62327 But generally if you need to do that, you would be better with re-design of your data/architecture. -- With best regards, Daniel Kluev -- http://mail.python.org/mailman/listinfo/python-list