On 7/21/2011 10:40 PM, Thomas 'PointedEars' Lahn wrote:
Billy Mays wrote:
On 07/21/2011 08:46 AM, Web Dreamer wrote:
If you do not want to use 'float()' try:
int(x.split('.')[0])
This is right.
Assuming that the value of `x' is in the proper format, of course. Else you
might easily cut to the first one to three digits of a string representation
(if `.' is the thousands separator of the locale, e. g.)
The point (which was clear to me) was to convert a properly formatted
string representation of a floating point number to an integer. We
might also assume the number could be a hex encoded float or be in
scientific notation. If the input is not properly formatted, it is
unreasonable for us to return a correct value.
But, the problem is the same as with int(float(x)), the integer number is
still not as close as possible as the original float value.
I would in fact consider doing this:
int(round(float(x)))
This is wrong, since there is a loss of information in the float cast:
>>> float('9007199254740993.0')
9007199254740992.0
Notice the last digit switched from a 3 to a 2? Floats in python don't
have arbitrary accuracy. You would need to import decimal and use it
for rounding to work properly.
It should be floor() though, for that is what int() does.
Um, what?
--
Bill
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