gc wrote:
Alternatively, is there a version of iterable multiplication that creates new objects rather than just copying the reference?
You can use a list comprehension: a, b, c, d, e = [dict() for i in xrange(5)] or a generator expression: a, b, c, d, e = (dict() for i in xrange(5)) -- Greg -- http://mail.python.org/mailman/listinfo/python-list
