Am 12.10.2011 10:22 schrieb Christian Wutte:
Hello all, as stated in the docs [1] os.startfile relies on Win32 ShellExecute(). So maybe someone can explain it to me, why there is no support for program arguments.
Because it is intended to start an arbitrary file of any type (.txt, .doc, ...) For this operations, there is no parameter support.
That's quite a pity since os.startfile is the easiest way for an elevated run (with 'runas' as option)
Obviously not. > and without arguments of limited use. So it isn't the asiest way. Have you tried os.system() and/or subprocess.Popen() resp. .call()? Thomas -- http://mail.python.org/mailman/listinfo/python-list
