On Thu, 27 Oct 2011 16:00:57 -0700, DevPlayer wrote:
> def isvalid_named_reference( astring ):
> # "varible name" is really a named_reference
> # import string # would be cleaner
I don't understand the comment about "variable name".
> valid_first_char =
> '_abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
> valid_rest =
> '_0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
This would be better:
import string
valid_first_char = '_' + string.ascii_letters
valid_rest = string.digits + valid_first_char
> # I think it's ok here for the rare type-check
> # as unicode named-references are not allowed
> if type(astring) is not str: return False
In Python 3 they are:
http://www.python.org/dev/peps/pep-3131/
> if len(astring) == 0: return False
> if astring[0] not in valid_first_char: return False
> for c in astring[1:]:
> if c not in valid_rest: return False
>
> # Python keywords not allowed as named references (variable names)
> for astr in ['and', 'assert', 'break', 'class', 'continue',
> 'def', 'del', 'elif', 'else', 'except', 'exec',
> 'finally', 'for', 'from', 'global', 'if', 'import',
> 'in', 'is', 'lambda', 'not', 'or', 'pass', 'print',
> 'raise', 'return', 'try', 'while', 'yield',]:
> if astring == astr: return False
You missed 'as' and 'with'. And 'nonlocal' in Python 3. Possibly others.
Try this instead:
from keywords import iskeyword
if iskeyword(astring): return False
--
Steven
--
http://mail.python.org/mailman/listinfo/python-list
