Peter Otten <__pete...@web.de> wrote:
> tinn...@isbd.co.uk wrote:
>
> > I want to sort a list of 'things' (they're fairly complex objects) by
> > the contents of one of the fields I can extract from the 'things'
> > using a Python function.
> >
> > So I have a list L which is a list of objects of some sort. I can
> > output the contents of a field in the list as follows:-
> >
> > for k in L:
> > print k.get_property('family-name')
> >
> > How can I sort the list first? As I said it seems like a methodcaller
> > is the answer but I don't see how. I want to sort the list of objects
> > not just produce a sorted list of names.
>
> The most obvious way is to use a custom function
>
> def get_family_name(obj):
> return obj.get_property("family-name")
> L.sort(key=get_family_name)
>
> However, since you already know about methodcaller
>
> """
> class methodcaller(builtins.object)
> | methodcaller(name, ...) --> methodcaller object
> |
> | Return a callable object that calls the given method on its operand.
> | After, f = methodcaller('name'), the call f(r) returns r.name().
> | After, g = methodcaller('name', 'date', foo=1), the call g(r) returns
> | r.name('date', foo=1).
> """"
>
> L.sort(key=methodcaller("get_property", "family-name"))
>
OK, thanks, just what I wanted.
--
Chris Green
--
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