On 12/30/11 11:51, dmitrey wrote:
how to get string name of a function that is n levels above
the current Python interpreter position?
Use the results of traceback.extract_stack()
from traceback import extract_stack
def one(x):
print "one", x
stk = extract_stack()
for mod, lineno, fun_name, call_code_text in stk:
print "[%s:%i] in %s" % (mod, lineno, fun_name)
def two(x):
print "two", x
one(x)
def three(x):
print "three", x
two(x)
three("Hi")
-tkc
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