On 1/25/2012 11:02 AM, Adam Mercer wrote:
Is this possible at all?
If you are not willing to tell Debian Squeeze users to install 2.7, or
that they cannot run your program, ask the bug reporter to tell you what
version of OpenSSL the system comes with and code it into your program.
Or possibly, depending on what you do with the version info and what the
differences are between versions, replace 'if version ...' constructs
with 'try ... except...' constructs.
On Mon, Jan 23, 2012 at 14:01, Adam Mercer<ramer...@gmail.com> wrote:
Hi
I'm trying to write a script that determines the version of OpenSSL
that python is linked against, using python-2.7 this is easy as I can
use:
import ssl
ssl.OPENSSL_VERSION
but unfortunately I need to support python-2.6, from an older script I
used the following:
import _ssl
ssl_lib = _ssl.__file__
to get the path to the _ssl.so module and then I parsed the output of
ldd (on linux) to get the path to the OpenSSL library and then parsed
the version from the filename. In other words it's very messy.
I had a little success using this approach but I have recently
received a bug report that this doesn't seem to work on Debian
Squeeze. When I try to query the __file__ attribute of the _ssl module
I get the following error:
import _ssl
_ssl.__file__
Traceback (most recent call last):
File "<stdin>", line 1, in<module>
AttributeError: 'module' object has no attribute '__file__'
Can anyone offer any suggestions as to what is going wrong with the
above code or offer an alternative way of determining the OpenSSl
version using python-2.6?
--
Terry Jan Reedy
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