On Thu, Feb 9, 2012 at 2:55 PM, Steven D'Aprano
<steve+comp.lang.pyt...@pearwood.info> wrote:
> If your data is humongous but only available lazily, buy more memory :)
Or if you have a huge iterable and only need a small index into it,
snag those first few entries into a list, then yield everything else,
then yield the saved ones:
def cycle(seq,n):
seq=iter(seq)
lst=[next(seq) for i in range(n)]
try:
while True: yield next(seq)
except StopIteration:
for i in lst: yield i
>>> list(cycle(range(10,20),2))
[12, 13, 14, 15, 16, 17, 18, 19, 10, 11]
Requires storage space relative to n, regardless of the length of the iterator.
ChrisA
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