why filter is bad when use lambda ?actually I think I can use lambda like
this： filter(lambda x:x==None,"|",split("|"))
On Wed, Aug 15, 2012 at 1:33 PM, Ramchandra Apte <maniandra...@gmail.com>wrote:
> filter is bad when you use lambda with it
> there are (good) cases for filter
>
>
> On 14 August 2012 22:39, Jean-Michel Pichavant <jeanmic...@sequans.com>wrote:
>
>> Ramchandra Apte wrote:
>>
>>> (Much) more Pythonic solution:
>>> >>> filter(None,"|".split("|"))
>>>
>>> On 14 August 2012 15:14, Andreas Tawn <andreas.t...@ubisoft.com <mailto:
>>> andreas.tawn@ubisoft.**com <andreas.t...@ubisoft.com>>> wrote:
>>>
>>> > I have a question about the split function? surpose a = "|",and
>>> when I use a.split("|") , I got the list
>>> > ['"",""] ,but I want to get the empty list,what should I do ?
>>>
>>> Something like...
>>>
>>> >>> [x for x in "|".split("|") if x]
>>> []
>>>
>>> Cheers,
>>>
>>> Drea
>>> --
>>>
>>> http://mail.python.org/**mailman/listinfo/python-list<http://mail.python.org/mailman/listinfo/python-list>
>>>
>>>
>>> A pythonic answer would be bottom-posted :p
>>
>> JM
>>
>>
>> PS : pylint raises a low warning about *filter* being non pythonic,
>> http://pylint-messages.**wikidot.com/messages:w0141<http://pylint-messages.wikidot.com/messages:w0141>
>> "les goûts et les couleurs ne se discutent pas"
>>
>
>
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