On 23 October 2012 12:07, Jean-Michel Pichavant <jeanmic...@sequans.com>wrote:
> ----- Original Message ----- > > > Thankyou.. but my problem is different than simply joining 2 lists > > and it is done now :).... > > > A lot of people though you were asking for joining lists, you description > was misleading. > > I'll take a guess: you want to flatten a list of list. > "Nested" list comprehensions can do the trick. > > aList =[[1,5], [2,'a']] > [item for sublist in aList for item in sublist] > > ... > [1, 5, 2, 'a'] > > I find it rather difficult to read though. We have a library function for this, in the one-and-only itertools. >>> listoflists = [list(range(x, 2*x)) for x in range(5)] > >>> listoflists > [[], [1], [2, 3], [3, 4, 5], [4, 5, 6, 7]] > >>> from itertools import chain > >>> list(chain.from_iterable(listoflists)) > [1, 2, 3, 3, 4, 5, 4, 5, 6, 7] It does exactly what it says... fast and easy-to-read.
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