Here's some example code. The input is a list which is a "matrix" of letters: a b a b b a
and I'd like to turn this into a Python array: 1 2 1 2 2 1 so 1 replaces a, and 2 replaces b. Here's the code I have so far: >>> L=['a b a\n','b b a\n'] >>> s=' '.join(L) >>> seq1=('a','b') >>> seq2=('1','2') >>> d = dict(zip(seq1,seq2)) >>> # Define method to replace letters according to dictionary (got this from >>> http://gomputor.wordpress.com/2008/09/27/search-replace-multiple-words-or-characters-with-python/). ... def replace_all(text, dic): ... for i, j in dic.iteritems(): ... text = text.replace(i, j) ... return text ... >>> seq = replace_all(s,d) >>> print seq 1 2 1 2 2 1 >>> seq '1 2 1\n 2 2 1\n' My question is how can I turn "seq" into a python array? Thanks Michael -- http://mail.python.org/mailman/listinfo/python-list