On Thursday, November 15, 2012 11:16:08 PM UTC-5, Ethan Furman wrote:
> Emile van Sebille wrote:
>
>
> >
>
> >> Using a decorator works when named arguments are not used. When named
>
> >> arguments are used, unexpected keyword error is reported. Is there a
>
> >> simple fix?
>
> >
>
> > Extend def wrapper(*args) to handle *kwargs as well
>
> >
>
> > Emile
>
> >
>
> >> Code:
>
> >> -----
>
> >>
>
> >> from functools import wraps
>
> >>
>
> >> def fix_args(fn):
>
> >> @wraps(fn)
>
> >> def wrapper(*args):
>
> so this line ^ becomes
>
> def wrapper(*args, **kwargs):
>
> >> args = (arg.replace('_', '') for arg in args)
>
> and add a line
>
> for k, v in kwargs:
>
> kwargs[k] = v.replace('_', '')
>
> >> return fn(*args)
>
> and this line ^ becomes
>
> return fn(*args, **kwargs)
>
> >> return wrapper
>
>
>
> ~Ethan~
Ethan,
I tried you code suggestions but got errors.
However, this works:
from functools import wraps
def fix_args(fn):
@wraps(fn)
def wrapper(*args, **kwargs):
args = (arg.replace('_', '') for arg in args)
for kv in kwargs:
kwargs[kv] = kwargs[kv].replace('_', '')
return fn(*args, **kwargs)
return wrapper
@fix_args
def foo(a1="", a2="", b1="", b2=""):
print(a1)
print(a2)
print(b1)
print(b2)
print ""
foo ('a1a1_x', 'a2a2_x', 'b1b1_x', 'b2b2_____x')
foo (a1='a1a1_x', a2='a2a2_x', b1='b1b1_x', b2='b2b2_____x')
foo ('a1a1_x', 'a2a2_x', b1='b1b1_x', b2='b2b2_____x')
Bruce
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