On Tue, Nov 20, 2012 at 10:29 AM, Marco <[email protected]> wrote:
> Because when I call an instance the __call__ method is called, and because
> the classes are instances of type, I thought when I call a Foo class this
> imply the call type.__call__(Foo), and so this one manages the Foo.__new__
> and Foo.__init__ calls:
Yes, that's right. Observe:
>>> class MetaFoo(type):
... def __call__(cls):
... print("before")
... self = super().__call__()
... print("after", self)
... return self
...
>>> class Foo(metaclass=MetaFoo):
... def __new__(cls):
... print("__new__")
... return super().__new__(cls)
... def __init__(self):
... print("__init__")
...
>>> f = Foo()
before
__new__
__init__
after <__main__.Foo object at 0x00C55410>
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