On Wed, Jan 30, 2013 at 12:56 PM, iMath <redstone-c...@163.com> wrote: > 在 2013年1月29日星期二UTC+8下午9时33分26秒，Steven D'Aprano写道： >> iMath wrote: > why [os.path.join(r'E:\Python', name) for name in []] returns >> [] ? Because you are iterating over an empty list, []. That list >> comprehension is the equivalent of: result = [] for name in []: >> result.append( os.path.join(r'E:\Python', name) ) Since you iterate over an >> empty list, the body of the loop never executes, and the result list remains >> empty. What did you expect it to do? -- Steven > > just in order to get the full path name of each file .
Then it's done exactly what it should. It's given you the full path of all of your list of zero files. ChrisA -- http://mail.python.org/mailman/listinfo/python-list
