On 02/06/2013 05:19 AM, Ulrich Eckhardt wrote:
Dave and Terry,
Thanks you both for your explanations! I really appreciate the time you
took.
Am 05.02.2013 19:07, schrieb Dave Angel:
<snip>
The main place where I see this type of problem is in a gui, where
you're defining a callback to be used by a series of widgets, but you
have a value that IS different for each item in the series. You write a
loop much like you did, and discover that the last loop value is the
only one used. The two cures above work, and you can also use lambda
creatively.
Careful, lambda does not work, at least not easily! The problem is that
lambda only creates a local, anonymous function, but any names used
inside this function will only be evaluated when the function is called,
so I'm back at step 1, just with even less obvious code.
Greetings!
Uli
I haven't been able to reconstruct it exactly, but here's the function
equivalent:
def myfunc2(i):
def myfunc2b():
print ("myfunc2 is using", i)
return myfunc2b
funcs = []
for i in range(5):
funcs.append(myfunc2(i))
print "Now doing the loop2"
for func in funcs:
func()
--
DaveA
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