On 01/04/2013 11:14, Ana Dionísio wrote:
So I have this script:
"
from numpy import array
Are you aware that this overrides the Python builtin array? It's
usually but not always better to do this
import numpy as np
vt = np.array(vt, dtype=dict)
vt=[0]*20
vt = array(vt, dtype=dict)
for t in range(20):
if t == 4:
vt[t]=1
else:
vt[t]=0
Why the loop, you've already initialise the array to zeroes?
"
And have this output:
[0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]
What I need is when t == 4 I need to put 1 in that position and in the next 3,
for example the following output:
[0 0 0 0 1 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0]
Do you have any suggestions?
Use slicing.
vt[4:8] = 1
I'm sorry if I can't explain this in a better way, English is not my first
language
Thank you
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