On Tue, Apr 9, 2013 at 1:37 AM, Roy Smith <r...@panix.com> wrote:
> I can't help point out, however, that if your initial implementation is to 
> have your code return a constant, it's pretty likely to be an optimum 
> solution in both time and space :-)

Likely, but not certain.

# 1
def fifty_stars():
  return "**************************************************"

# 2
fifty_stars=lambda "*"*50

Okay, that's just getting 2AM stupid now. :)

ChrisA
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