Roy Smith wrote:
> Andrew Durdin <[EMAIL PROTECTED]> wrote:
>>Corrected version:
>>    result = [(lambda: expr0), lambda: expr1][bool(cond)]()
Sorry, I thought cond was a standard boolean.
Better is:
     result = [(lambda: true_expr), lambda: false_expr][not cond]()

--Scott David Daniels
[EMAIL PROTECTED]
-- 
http://mail.python.org/mailman/listinfo/python-list

Reply via email to