On 5/16/2013 11:00 AM, loial wrote:
I want to split a string so that I always return everything BEFORE the LAST
underscore
HELLO_xxxxxxxx.lst # should return HELLO
HELLO_GOODBYE_xxxxxxxx.ls # should return HELLO_GOODBYE
I have tried with rsplit but cannot get it to work.
Any help appreciated
>>> "HELLO_GOODBYE_xxxxxxxx.ls".rpartition('_')
('HELLO_GOODBYE', '_', 'xxxxxxxx.ls')
>>> "HELLO_GOODBYE_xxxxxxxx.ls".rsplit('_', 1)
['HELLO_GOODBYE', 'xxxxxxxx.ls']
>>> "HELLO_GOODBYE_xxxxxxxx.ls".rpartition('_')[0]
'HELLO_GOODBYE'
>>> "HELLO_GOODBYE_xxxxxxxx.ls".rsplit('_', 1)[0]
'HELLO_GOODBYE'
For the future, getting help works better if you show what you tried,
and what it produced.
--Ned.
--
http://mail.python.org/mailman/listinfo/python-list