Thanks.
On Thu, Jun 6, 2013 at 4:49 PM, Cameron Simpson <c...@zip.com.au> wrote:
> On 06Jun2013 03:50, Avnesh Shakya <avnesh.n...@gmail.com> wrote:
> | hi,
> | I am running a python script and it will create a file name like
> filename0.0.0 and If I run it again then new file will create one more like
> filename0.0.1...... my code is-
> |
> | i = 0
> | for i in range(1000):
> | try:
> | with open('filename%d.%d.%d.json'%(0,0,i,)): pass
> | continue
> | except IOError:
> | dataFile = file('filename%d.%d.%d.json'%(0,0,i,), 'a+')
> | break
> | But It will take more time after creating many files, So i want to store
> value of last var "i" in a variable so that when i run my script again then
> I can use it. for example-
> | my last created file is filename0.0.27 then it should
> store 27 in a variable and when i run again then new file should be created
> 0.0.28 according to last value "27", so that i could save time and it can
> create file fast..
> |
> | Please give me suggestion for it.. How is it possible?
>
> Write it to a file? Read the file next time the script runs?
>
> BTW, trying to open zillions of files is slow.
> But using listdir to read the directory you can see all the names.
> Pick the next free one (and then test anyway).
> --
> Cameron Simpson <c...@zip.com.au>
>
> The mark must be robust enough to survive MP3 transmission over the
> Internet,
> but remain inaudible when played on the yet to be launched DVD-Audio
> players.
> - the SDMI audio watermarkers literally ask for the impossible, since all
> audio compressors aim to pass _only_ human perceptible data
> http://www.newscientist.com/news/news.jsp?id=ns224836
> --
> http://mail.python.org/mailman/listinfo/python-list
>
--
http://mail.python.org/mailman/listinfo/python-list
