On 4 July 2013 17:54, Rotwang <sg...@hotmail.co.uk> wrote: > 53*(63**1000000 - 1)//62
Or about 10**10**6.255 (so about 1.80M digits long). For the unicode side (Python 3, in other words) and reusing your math (ya better hope it's right!), you are talking: 97812*((97812+2020)**1000000 - 1)/(97812+2020-1) Or about 10**10**6.699 Which has about 5.00M digits. Good luck running out. -- http://mail.python.org/mailman/listinfo/python-list
