Στις 17/9/2013 4:00 μμ, ο/η Roy Smith έγραψε:
In article <l19gdf$psh$1...@dont-email.me>, Ferrous Cranus <nikos.gr...@gmail.com> wrote:o want to avoid having to type somehting like this: if person="George": times in range(0, 5): Why it gives me an error when i'm trying to write it like this: if person="George" for times in range(0, 5):Step One when reporting a problem is don't just tell us you got an error. Tell us what the error is. Cut and paste the exact text of the full error message. Although, in this case, it's pretty easy to guess that it was a syntax error :-) I'm not sure where to start. First, the '=' in 'person="George"' should be '=='. In Python, '=' is used for assignment, '==' is used for equality testing. Next, if you want to use the 1-line version of 'if', you need a ':' after the condition. Something like: if person == 'George': print 'foo' but it's generally considered poor style to use 1-line if statements. Just write it on two lines: if person == 'George': print 'foo' They just discovered a huge newline vein in Montana and they're mining the things like crazy. There's no shortage of them so feel free to use as many as you like. They even get recycled. But, I'm not even sure you can put a 'for' statement as the body of a 1-line 'if'. I've never tried it before, and my one experiment now got me a syntax error. Even if it turns out to be legal and I just haven't got the details right, it's just The Wrong Thing To Do.
I just want to say tot he program that that only run the for statement if and only if person=='George' I dont see nay reason as to why this fails perhaps like: for times in range(0, 5) if person=='George': but that fails too... there must be written on soem way. -- https://mail.python.org/mailman/listinfo/python-list
