On Thu, 12 Dec 2013 00:59:42 +0000, MRAB wrote: >> table = [(x, i) for i,x in enumerate(iterable)] >> table.sort() > > This looks wrong to me: > >> for x, i in table: >> table[i] = x
Yes, you're right, I over-simplified the example, and in doing so
introduced a bug. What I actually use is:
for i, x in enumerate(table):
table[i] = x[1]
modulo any further bugs introduced while copying and pasting :-)
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Steven
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