On 2014-01-14 19:24, Mike wrote:
Hello,
I confudsed,need printer the value of list (this is reaer from csv) . The
reader is ok, but my problem is in the print moment because printer only the
last value. For example my csv is:
[........]
us...@example.com;user1;lastName;Name
us...@example.com;user2;lastName;Name
[........]
But when execute the script I view the print is only the last user
[........]
ca us...@example.com displayName 'user2' sn 'lastName' cn 'Name'
[........]
And I need the next printer
[........]
ca us...@example.com displayName 'User1' sn ''lastName" cn 'Name'
ca us...@example.com displayName 'User2' sn ''lastName" cn 'Name'
[........]
My script is
[........]
#!/usr/bin/python
import csv
with open ('users.csv', 'rb') as f:
reader = csv.reader (f, delimiter=';' ) #delimiter tabulador
for row in reader:
mail = row [0]
name = row [3]
lastname = row [2]
This line is indented the same amount as the 'for' loop, which means
that it will be executed after the loop has finished.
print "ma {} displayName '{}' sn '{}'".format(mail,name,lastname)
You don't need to close the file here because the 'with' statement will
do that for you.
f.close()
[........]
Thanks.
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