vch wrote: > Here's an example from some book: > > def foo(n): > s = [n] > def bar(i): > s[0] += i > return s[0] > return bar > > what I don't understand is how this example works, taking into account > the LGB rule. I thought that s is not accessible from bar, but it is, > apparently. Why?
Nested Scopes (Since Python 2.1): http://www.python.org/peps/pep-0227.html -- http://mail.python.org/mailman/listinfo/python-list
