On 02/12/2014 12:17 PM, Tobiah wrote:
I do this:
a = 'lasdfjlasdjflaksdjfl;akjsdf;kljasdl;kfjasl'
b = 'lasdfjlasdjflaksdjfl;akjsdf;kljasdl;kfjasl'
print
print id(a)
print id(b)
And get this:
True
140329184721376
140329184721376
This works for longer strings. Does python
compare a new string to every other string
I've made in order to determine whether it
needs to create a new object?
Thanks,
Tobiah
Yes.
Kind of: It's a hash calculation not a direct comparison, and it's
applied to strings of limited length. Details are implementation (and
perhaps version) specific. The process is called "string interning".
Google and wikipedia have lots to say about it.
Gary Herron
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