In article <mailman.7122.1392756159.18130.python-l...@python.org>, Terry Reedy <tjre...@udel.edu> wrote:
> On 2/18/2014 11:47 AM, Chris Angelico wrote: > > I call this "Russian Exception Roulette". It came about because of > > some discussions on python-ideas regarding the new PEP 463 and > > exception handling. > > > > try: > > exc = getattr(__builtins__,random.choice(list(filter(lambda x: > > x.endswith("Error"),dir(__builtins__))))) > > f() > > except exc: > > print("You win!") > > > > Given a function f(), defined elsewhere, what will this do? > > I am not sure what you are asking or what your point is. If f happens to > raise the randomly selected exception, it prints 'You win!', otherwise > it does nothing. def f(): print("You win!") problem solved :-) -- https://mail.python.org/mailman/listinfo/python-list