On Tue, Mar 4, 2014 at 10:05 PM, Gregory Ewing <greg.ew...@canterbury.ac.nz> wrote: > Chris Angelico wrote: >> >> In constant space, that will produce the sum of two infinite sequences >> of digits. > > > It's not constant space, because the nines counter > can grow infinitely large.
Okay, okay, technically yes. But the counter can go a long way up before it takes up any additional space, so all that's really saying is that this has a major flaw with anything that produces a long stream of nines. It can't tell the difference between .99999999999999998 and .999999999999999999999999[11] where the 11 suddenly carries and it has to flip it all back. Anyway, that was like ten minutes' knocking-together work, you can't expect it to be perfect. I'm amazed it even worked. :) ChrisA -- https://mail.python.org/mailman/listinfo/python-list
