On Sat, Jun 7, 2014 at 9:17 PM, 1989lzhh <1989l...@gmail.com> wrote: > def make(): > def jit(sig): > def wrap(function): > sig=sig[0] # unbound local error, if change to sig='' would be > just fine > return function > return wrap > return jit > jit=make() > @jit('') > def f(): > pass > > It is strange that the interpreter complain about unbound local error. > please give me some suggestion, thanks! > Ps: I am using python 2.7
It's quite simple. You're assigning to the name 'sig' inside the function 'wrap', which means that - in the absence of a declaration - 'sig' is a local name. But before you assign anything to it, you first try to reference it, by subscripting it (sig[0]). Python doesn't have a rule about pulling something in from another scope at the same time as making it local (some languages do, and it's rather handy, but it can only work with variable declarations), so what you're attempting to do there simply won't work. But it seems a little odd anyway. Why do you take the first element of sig every time the inner function is called? Surely you want to do that just once? ChrisA -- https://mail.python.org/mailman/listinfo/python-list