On Wed, 3 Sep 2014 13:11:51 -0600, Ian Kelly <ian.g.ke...@gmail.com> wrote:
>On Wed, Sep 3, 2014 at 12:49 PM, Seymore4Head ><Seymore4Head@hotmail.invalid> wrote: >> On Wed, 03 Sep 2014 14:10:42 -0400, Seymore4Head >> <Seymore4Head@Hotmail.invalid> wrote: >> >>>import math >>>import random >>>import sys >>>b=[] >>>steve = [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89] >>>for x in steve: >>> print (steve[x]) >>> >>>Traceback (most recent call last): >>> File "C:\Functions\blank.py", line 7, in <module> >>> print (steve[x]) >>>IndexError: list index out of range >> >> Ok, I understand now that x is actually the first item in the list. >> What I want is a loop that goes from 1 to the total number of items in >> the list steve. > >If you want the indexes also, you can do this: > >for i, x in enumerate(steve): > print(i, x) > >If you really want just the indexes and not the values, then you can do this: > >for i in range(len(steve)): > print(i) > >Most of the time though you will not need the indexes, and it will be >simpler just to work with the values by looping directly over the >list. I figured it out now. I was expecting x to be a number and not an item. I used for i in range(len(steve)): Thanks Printing x to see what it is instead of assuming what it is really helps. I am getting there. I just have to take smaller steps. -- https://mail.python.org/mailman/listinfo/python-list
