On Friday 26 September 2014 23:49:43 Seymore4Head did opine And Gene did reply: > Still practicing. Since this is listed as a Pseudocode, I assume this > is a good way to explain something. That means I can also assume my > logic is fading with age. > http://en.wikipedia.org/wiki/Leap_year#Algorithm > > Me trying to look at the algorithm, it would lead me to try something > like: > if year % 4 !=0: > return False > elif year % 100 !=0: > return True > elif year % 400 !=0: > return False > > **** Since it is a practice problem I have the answer: > def is_leap_year(year): > return ((year % 4) == 0 and ((year % 100) != 0 or (year % 400) == 0)) > > I didn't have any problem when I did this: > > if year % 400 == 0: > print ("Not leap year") > elif year % 100 == 0: > print ("Leap year") > elif year % 4 == 0: > print ("Leap year") > else: > print ("Not leap year")
Which is, except for language syntax to state it, exactly the same as is quoted for this problem in the original K&R C manual. Is there anything new? Cheers, Gene Heskett -- "There are four boxes to be used in defense of liberty: soap, ballot, jury, and ammo. Please use in that order." -Ed Howdershelt (Author) Genes Web page <http://geneslinuxbox.net:6309/gene> US V Castleman, SCOTUS, Mar 2014 is grounds for Impeaching SCOTUS -- https://mail.python.org/mailman/listinfo/python-list
