On Wed, Oct 22, 2014 at 4:30 PM, Seymore4Head <Seymore4Head@hotmail.invalid> wrote: > def nametonumber(name): > lst=[""] > for x,y in enumerate (name): > lst=lst.append(y) > print (lst) > return (lst) > a=["1-800-getcharter"] > print (nametonumber(a))#18004382427837 > > > The syntax for when to use a () and when to use [] still throws me a > curve. () is tuples which are immutable which means that the items can't be changed. [] is list which means that each item can be changed. Tuples are useful because they can be used as keys in dictionaries and are guarantied not to change. Lists are useful because they can be updated.
What you are doing confuses me. You don't use x, which is the enumerated value. FIrst lst should be lst = [] . You don't need to set the first element in the list to an empty string. You just want to establish that you have an empty list called lst Second, you don't need lst = lst.append(y) because you can just say lst.append(y). This will append the y value to the end of the list. As to converting letters to the corresponding numbers on a phone keypad, you don't show you code here for that > > For now, I am trying to end up with a list that has each character in > "a" as a single item. > > I get: > None > None > -- > https://mail.python.org/mailman/listinfo/python-list -- Joel Goldstick http://joelgoldstick.com -- https://mail.python.org/mailman/listinfo/python-list
