On 05Dec2014 15:01, telnetgm...@gmail.com <telnetgm...@gmail.com> wrote:
Why the following code gives me errors??? And why the print statement run 2
times? I'll be appreciated your helps, thanks,
addrnum_dict = {'a':1,'b':2}
def orderaddrtimes():
global addrnum_dict
print type(addrnum_dict)
addrnum_dict = sorted(addrnum_dict.iteritems(), key=lambda d:d[1], reverse =
True)
Because of the line above. The return value of "sorted()" is a list. You assign
that list to "addrnum_dict". That name now refers to the list from "sorted()".
Because you call the orderaddrtimes() function twice, the second time you call
it "addrnum_dict" is the list from the first call. Not a dict.
You would be best to not assign the result of "sorte()" to "addrnum_dict".
Assign it to something else.
#addrnum_dict = OrderedDict(sorted(addrnum_dict.items(), key=lambda t: t[0]))
if __name__ == '__main__':
kinds = ["a","b"]
for tmp_kind in kinds:
orderaddrtimes()
######################
errors:
python aaa.py
<type 'dict'>
<type 'list'>
Traceback (most recent call last):
File "aaa.py", line 16, in <module>
orderaddrtimes()
File "aaa.py", line 11, in orderaddrtimes
addrnum_dict = sorted(addrnum_dict.iteritems(), key=lambda d:d[1], reverse =
True)
AttributeError: 'list' object has no attribute 'iteritems'
Thank you for including the complete error output. This is very helpful, and
often essential.
Cheers,
Cameron Simpson <c...@zip.com.au>
Who are all you people and why are you in my computer? - Kibo
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