Shambhu Rajak wrote: > I have a string that I get as an output of a command as: > '\x01\x00\x00\x00\x00\x00\x00\x00\x0c\x00\x00\x0010232ae8944a\x02\x00\x00\x00\x00\x00\x00\x00\n' > > I want to fetch '10232ae8944a' from the above string. > > I want to find a re pattern that could replace all the \x01..\x0z to be > replace by empty string '', so that I can get the desired portion of > string > > Can anyone help me with a working regex for it.
I think you want the str.tranlate() method rather than a regex. Assuming you are using Python 2: >>> delenda = "".join(map(chr, range(32))) >>> identity = "".join(map(chr, range(256))) >>> '\x01\x00\x00\x00\x00\x00\x00\x00\x0c\x00\x00\x0010232ae8944a\x02\x00\x00\x00\x00\x00\x00\x00\n'.translate(identity, delenda) '10232ae8944a' With Python3: >>> mapping = dict.fromkeys(range(32)) >>> '\x01\x00\x00\x00\x00\x00\x00\x00\x0c\x00\x00\x0010232ae8944a\x02\x00\x00\x00\x00\x00\x00\x00\n'.translate(mapping) '10232ae8944a' -- https://mail.python.org/mailman/listinfo/python-list
