On 2015-03-02, greymausg <m...@mail.com> wrote: > On 2015-03-02, Steven D'Aprano <steve+comp.lang.pyt...@pearwood.info> wrote: >> greymausg wrote: >> >>> I have a csv file, the first item on a line is the date in the format >>> 2015-03-02 I try to get that as a date by date(row[0]), but it barfs, >>> replying "Expecting an integer". (I am really trying to get the offset >>> in weeks from that date to today()) >> >> What is "date"? Where does it come from? >> >> If it is your own function, then we cannot help you unless you show us the >> code for it. >> >> If you mean the standard library date, then you should say so. >> >> >> py> from datetime import datetime >> py> today = datetime.today() >> py> astring = "2014-12-27" >> py> another_day = datetime.strptime(astring, "%Y-%m-%d") >> py> difference = today - another_day >> py> difference.days >> 65 >> py> difference.days/7 # weeks >> 9.285714285714286 >> >> > > Standard datetime.date, if it were not, I would have written. > Will try, thanks for the info. > >
Thanks to all, the strptime did the trick, after I realized that I was comparing a 2digit year to a 4digit. -- greymaus . . ... -- https://mail.python.org/mailman/listinfo/python-list
