John Pote <johnhp...@o2.co.uk> writes:
> I recently had the problem of converting from an integer to its
> representation as a list of binary bits, each bit being an integer 1
> or 0, and vice versa.
Is this a homework assignment?
> E.G.
> 0x53
> becomes
> [ 0, 1, 0, 1, 0, 0, 1, 1 ]
>>> foo = 4567
>>> foo
4567
>>> "{foo:d}".format(foo=foo)
'4567'
>>> "{foo:b}".format(foo=foo)
'1000111010111'
>>> foo_binary_text = "{foo:b}".format(foo=foo)
>>> foo_binary_digits = list(foo_binary_text)
>>> foo_binary_digits
['1', '0', '0', '0', '1', '1', '1', '0', '1', '0', '1', '1', '1']
> Just wondered if there was a neat way of doing this without resorting
> to a bit bashing loop.
Python's string formatting and sequence types are quite powerful.
--
\ “As far as the laws of mathematics refer to reality, they are |
`\ not certain, and as far as they are certain, they do not refer |
_o__) to reality.” —Albert Einstein, 1983 |
Ben Finney
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