On 06/03/2015 01:41 PM, Mohan Mohta wrote:
Hello
I am trying to create multiple thread through the below program but I am
getting an error
#! /usr/bin/python
import os
import subprocess
import thread
import threading
from thread import start_new_thread
def proc(f) :
com1="ssh -B "
com2=line.strip('\n')
com3= " uname -a"
co=str("ssh -B ")+ str(com2) + str(" uname -a")
subprocess.call(co,shell=True)
print "----------------------------"
return
f = open('/tmp/python/1')
for line in f:
t=thread.start_new_thread(proc(f),())
You are calling the function f yourself, but what you want here is for
the thread to call f once it's running.
So do
t=thread.start_new_thread(proc, (f,)) # Procedure to call and a
tuple of args for it.
t.start()
I don't think the thread has a start method.
f.close()
c = raw_input(" Type anything to quit")
Execution output:
Linux abc.myhomenetwork.com 2.6.18-348.25.1.el5 #1 SMP Thu Apr 10 06:32:45 EDT
2014 x86_64 x86_64 x86_64 GNU/Linux
----------------------------
Traceback (most recent call last):
File "./readfile1.py", line 19, in <module>
t=thread.start_new_thread(proc(f),())
TypeError: first arg must be callable
You should probably also consider using the higher-level threading
module rather than the lower level thread module.
(Also consider using Python3 instead of Python2.)
Gary Herron
--
Dr. Gary Herron
Department of Computer Science
DigiPen Institute of Technology
(425) 895-4418
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