On Wed, 22 Jul 2015 07:12 am, max scalf wrote:
> Hello all,
>
> For Each SecurityGroup, how can i convert that into a List that in turn
> will have a dictionary of the cidr block, protocol type and the port...
Start with this:
def sg_to_list(sg):
return [rule_to_dict(r) for r in sg.rules]
def rule_to_dict(rule):
d = {} # expected {'cidr': '0.0.0.0/0', 'proto': 'tcp', 'port': 80}
d['cidr'] = rule.cidr
d['proto'] = rule.proto
d['port'] = rule.port
return d
and adjust until working.
--
Steven
--
https://mail.python.org/mailman/listinfo/python-list