On Tue, 11 Aug 2015 17:01:24 -0700, Ltc Hotspot wrote:
> What is the list equivalent to line 12: ncount.sort(reverse=True)
>
> count = dict()
> fname = raw_input("Enter file name: ")#
> handle = open (fname, 'r')#
> for line in handle:
> if line.startswith("From "):
> address = line.split()[5]
> line = line.rstrip()
> count[address] = count.get(address, 0) + 1
At this point, count seems to be a dictionary of address: count of lines
> for key,val in count.items():
> ncount = (key,val) ncount.sort(reverse=True) print key,val
ncount is a single key-value pair. Why are you trying to sort ncount?
Do you want results ordered by count?
First, change your dictionary into a list of tuples:
ncount = [(a,c) for a,c in count.items()]
Then sort ncount on the second field of the tuple:
ncount.sort(key = lambda x: x[1], reverse=True)
print ncount
--
Denis McMahon, denismfmcma...@gmail.com
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