Neal Becker <ndbeck...@gmail.com> writes: > Trying regex 2015.07.19 > > I'd like to match recursive parenthesized expressions, with groups such that > '(a(b)c)' > > would give > group(0) -> '(a(b)c)' > group(1) -> '(b)' > > but that's not what I get > > import regex > > #r = r'\((?>[^()]|(?R))*\)' > r = r'\(([^()]|(?R))*\)' > #r = r'\((?:[^()]|(?R))*\)' > m = regex.match (r, '(a(b)c)')
The (?R) syntax is Perl -- it's no implemented in Python. Python and Perl regexs are very similar in syntax (for very good reasons) but neither (?R) nor the numbered or named versions of it are in Python. -- Ben. -- https://mail.python.org/mailman/listinfo/python-list
