On 23/09/2015 17:32, Denis McMahon wrote:
On Tue, 22 Sep 2015 14:43:55 -0700, Chris Roberts wrote:
results = 134523 #(Integer)
This appears to be an integer expressed (presumably) in base 10 with 6
digits
Desired:
results = [1, 2, 3, 4, 5, 2, 3] #(INDEX)
This appears to be a python list of 7 elements, with the first and the
the third through seventh elements corresponding to the first and the
second through sixth most significant digits respectively of the
previously discussed integer.
I can't actually see any direct method of creating the list given from
the number given.
However, if I understand the intent of the question you meant to ask, you
might find that the following code does something interesting:
x = 9876543210
y = []
while x > 0:
y.append(x % 10)
x = int(x / 10)
y = list(reversed(y))
print y
I like the math approach even if the pythonic list string is quicker...
One 'math' way would also be (avoiding the list reverse, but need to
import math):
>>> import math
>>> result = 1234567
>>> digits = int(math.log10(result) + 1)
>>> y = []
>>> for x in range(digits, 0, -1):
number = result % (10 ** x) / (10 **(x-1))
y.append(int(number))
>>> y
[1, 2, 3, 4, 5, 6, 7]
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